(x^2)+x=392

Solution for (x^2)+x=392 equation:

(x^2)+x=392

We move all terms to the left:

(x^2)+x-(392)=0

a = 1; b = 1; c = -392;
Δ = b2-4ac
Δ = 12-4·1·(-392)
Δ = 1569
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{1569}}{2*1}=\frac{-1-\sqrt{1569}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{1569}}{2*1}=\frac{-1+\sqrt{1569}}{2}
$